A solid shaft is transmitting 2 MW at 270 r.p.m. Determine the diameter of the shaft. Take the maximum allowable shear stress as 72 MPa.

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Question: A solid shaft is transmitting 2 MW at 270 r.p.m. Determine the diameter of the shaft. Take the maximum allowable shear stress as 72 MPa.

Answer:

Given data:

Power transmitted by the shaft (P) = 2 MW, 

Speed of the shaft (N) = 270 rpm,

The maximum allowable shear stress

 = 72 MPa.
To calculate mean torque.


Substitute 2 MW for P and 270 rpm for N  in the above equation.


Write the equation of the shear stress.
Here, d  is the diameter of the shaft.

Rearrange the above equation.

Substitute 70735.530 N-m for  , 72 MPa for  in the above equation.


Thus, the diameter of the shaft is 171.038 mm.




























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