A car of mass 500 kg moving at a speed of 36 km/hr is stopped by applying brakes in 10 s. What is the force applied by the brakes?

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Given data:
Mass of the car (m) = 500 kg, Speed of the car (u) = 36 km/h, time required to stop the car (t) = 10 s.

Find acceleration of the car after applying break to write the equation of the uniform acceleration.
v = u + at  ......(1)
Here, v is the speed of the car after car stopped i.e. 0 m/s and a is the acceleration of the car.

Convert speed of the car from km/h to m/s.
u = 36 × (1000/3600)
u = 10 m/s

Substitute 10 m/s for u, 10 s for t and 0 m/s for v in the equation (1).
0 = 10 + (10a)
a = -1 m/s²

According to defination of the force, write the equation of the force.
F = ma
Substitute -1 m/s² for a and 500 kg for m in the above equation.
F = (-1 ×500)
F = -500 N
The negative sign represents that this force opposes the motion of the car.

Thus, the brake force required to stop the car is 500 N.

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